Discrepancy between Julian Year and Tropical Year
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Theorem
The Julian year and the tropical year differ such that the Julian calendar becomes $1$ day further out approximately every $128$ years.
Proof
By definition, the length $Y_T$ of the tropical year is defined as $\approx 365 \cdotp 24219 \, 878$ days
By definition of the Julian year:
- $Y_J = \begin{cases} 366 \, \text {days} & : 4 \divides y \\
365 \, \text {days} & : 4 \nmid y \end{cases}$ where:
- $Y_J$ denotes the length of the Julian year in days
- $y$ denotes the number of the year
- $4 \divides y$ denotes that $y$ is divisible by $4$
- $4 \nmid y$ denotes that $y$ is not divisible by $4$.
Thus:
\(\ds 4 Y_J\) | \(=\) | \(\ds 3 \times 365 + 366\) | considering $4$ consecutive Julian years | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds Y_J\) | \(=\) | \(\ds \frac {1461} 4\) | |||||||||||
\(\ds \) | \(=\) | \(\ds 365 \cdotp 25\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds Y_J - Y_T\) | \(\approx\) | \(\ds 365 \cdotp 25 - 365 \cdotp 24219 \, 878\) | |||||||||||
\(\ds \) | \(\approx\) | \(\ds 0 \cdotp 0078013\) | ||||||||||||
\(\ds \) | \(\approx\) | \(\ds \frac 1 {128 \cdotp 18}\) |
Thus the mean Julian year is $\dfrac 1 {128 \cdotp 18}$ days longer than the tropical year.
This means that after approximately $128$ Julian years, the Julian calendar starts one day later relative to the tropical year.
$\blacksquare$
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $365 \cdotp 2422$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $365 \cdotp 24219 \, 878$