Divisor Count of 1638
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Example of Use of Divisor Count Function
- $\map {\sigma_0} {1638} = 24$
where $\sigma_0$ denotes the divisor count function.
Proof
From Divisor Count Function from Prime Decomposition:
- $\ds \map {\sigma_0} n = \prod_{j \mathop = 1}^r \paren {k_j + 1}$
where:
- $r$ denotes the number of distinct prime factors in the prime decomposition of $n$
- $k_j$ denotes the multiplicity of the $j$th prime in the prime decomposition of $n$.
We have that:
- $1638 = 2 \times 3^2 \times 7 \times 13$
Thus:
\(\ds \map {\sigma_0} {1638}\) | \(=\) | \(\ds \map {\sigma_0} {2^1 \times 3^2 \times 7^1 \times 13^1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {1 + 1} \paren {2 + 1} \paren {1 + 1} \paren {1 + 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 24\) |
The divisors of $1638$ can be enumerated as:
- $1, 2, 3, 6, 7, 9, 13, 14, 18, 21, 26, 39, 42, 63, 78, 91, 117, 126, 182, 234, 273, 546, 819, 1638$
$\blacksquare$