Dudeney's Property of 2592
Theorem
- $2592 = 2^5 \times 9^2$
It is the only number $n$ that has the property that:
- $n = \sqbrk {abcd} = a^b \times c^d$
where $\sqbrk {abcd}$ denotes the decimal representation of $n$.
Proof
First we verify that $2592$ does indeed satisfy the given property.
\(\ds 2592\) | \(=\) | \(\ds 2^5 \times 3^4\) | Prime Decomposition of $2592$ | |||||||||||
\(\ds \) | \(=\) | \(\ds 2^5 \times \paren {3^2}^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^5 \times 9^2\) |
$\Box$
It remains to be shown that this is the only such number.
Because $\sqbrk {abcd} = a^b \times c^d$, neither $a^b$ nor $c^d$ can have more than $4$ digits.
Hence, for each digit, the highest power is:
\(\ds 1^9\) | \(=\) | \(\ds 1\) | ||||||||||||
\(\ds 2^9\) | \(=\) | \(\ds 512\) | ||||||||||||
\(\ds 3^8\) | \(=\) | \(\ds 6561\) | ||||||||||||
\(\ds 4^6\) | \(=\) | \(\ds 4096\) | ||||||||||||
\(\ds 5^5\) | \(=\) | \(\ds 3125\) | ||||||||||||
\(\ds 6^5\) | \(=\) | \(\ds 7776\) | ||||||||||||
\(\ds 7^4\) | \(=\) | \(\ds 2401\) | ||||||||||||
\(\ds 8^4\) | \(=\) | \(\ds 4096\) | ||||||||||||
\(\ds 9^4\) | \(=\) | \(\ds 6561\) |
Neither $a$ or $c$ can be zero, or that would make $\sqbrk {abcd} = 0$.
Suppose $a = 1$ or $b = 0$.
Then:
- $\sqbrk {abcd} = c^d$
Apart from the above powers which have $4$ digits, we also have:
\(\ds 3^7\) | \(=\) | \(\ds 2187\) | ||||||||||||
\(\ds 4^5\) | \(=\) | \(\ds 1024\) | ||||||||||||
\(\ds 6^4\) | \(=\) | \(\ds 1296\) |
Hence, by inspection, it is seen that none of these fit the pattern $\sqbrk {1bcd}$ or $\sqbrk {a0cd}$.
Similarly, suppose $c = 1$ or $d = 0$.
Then:
- $\sqbrk {abcd} = a^b$
Again, by inspection, it is seen that none of the above $4$-digit powers fit the pattern $\sqbrk {ab1d}$ or $\sqbrk {abc0}$.
Suppose either $a^b$ or $c^d$ has $4$ digits.
Then the other is less than $10$, giving:
\(\ds n^1\) | \(=\) | \(\ds n\) | ||||||||||||
\(\ds 2^2\) | \(=\) | \(\ds 4\) | ||||||||||||
\(\ds 2^3\) | \(=\) | \(\ds 8\) | ||||||||||||
\(\ds 3^2\) | \(=\) | \(\ds 9\) |
We try multiplying these by all the above $4$-digit powers such that their product is $4$ digits (there are not many).
First note that $1^1$ can be ruled out as none of these $4$-digit powers either begins or ends with $11$.
\(\ds 3^7 \times 2^1\) | \(=\) | \(\ds 2187 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 4374\) | ||||||||||||
\(\ds 3^7 \times 3^1\) | \(=\) | \(\ds 2187 \times 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 6561\) | ||||||||||||
\(\ds 3^7 \times 4^1\) | \(=\) | \(\ds 3^7 \times 2^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2187 \times 4\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 8748\) |
\(\ds 4^5 \times 2^1\) | \(=\) | \(\ds 1024 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2048\) | ||||||||||||
\(\ds 4^5 \times 3^1\) | \(=\) | \(\ds 1024 \times 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 3072\) | ||||||||||||
\(\ds 4^5 \times 4^1\) | \(=\) | \(\ds 4^5 \times 2^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1024 \times 4\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 4096\) | ||||||||||||
\(\ds 4^5 \times 5^1\) | \(=\) | \(\ds 1024 \times 5\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 5120\) | ||||||||||||
\(\ds 4^5 \times 6^1\) | \(=\) | \(\ds 1024 \times 6\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 6144\) | a near miss: $6^1 \times 4^5 = 6144$ | |||||||||||
\(\ds 4^5 \times 7^1\) | \(=\) | \(\ds 1024 \times 7\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 7168\) | ||||||||||||
\(\ds 4^5 \times 8^1\) | \(=\) | \(\ds 4^5 \times 2^3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1024 \times 8\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 8192\) | ||||||||||||
\(\ds 4^5 \times 9^1\) | \(=\) | \(\ds 4^5 \times 3^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1024 \times 9\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 9216\) |
\(\ds 4^6 \times 2^1\) | \(=\) | \(\ds 4096 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 8192\) |
\(\ds 5^5 \times 2^1\) | \(=\) | \(\ds 3125 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 6250\) | ||||||||||||
\(\ds 5^5 \times 3^1\) | \(=\) | \(\ds 3125 \times 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 9375\) |
\(\ds 6^4 \times 2^1\) | \(=\) | \(\ds 1296 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2592\) | ||||||||||||
\(\ds 6^4 \times 3^1\) | \(=\) | \(\ds 1296 \times 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 3888\) | ||||||||||||
\(\ds 6^4 \times 4^1\) | \(=\) | \(\ds 6^4 \times 2^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1296 \times 4\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 5184\) | ||||||||||||
\(\ds 6^4 \times 5^1\) | \(=\) | \(\ds 1296 \times 5\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 6480\) | ||||||||||||
\(\ds 6^4 \times 6^1\) | \(=\) | \(\ds 1296 \times 6\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 7776\) | ||||||||||||
\(\ds 6^4 \times 7^1\) | \(=\) | \(\ds 1296 \times 7\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 9072\) |
\(\ds 7^4 \times 2^1\) | \(=\) | \(\ds 2401 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 4802\) | ||||||||||||
\(\ds 7^4 \times 3^1\) | \(=\) | \(\ds 2401 \times 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 7203\) | ||||||||||||
\(\ds 7^4 \times 4^1\) | \(=\) | \(\ds 7^4 \times 2^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2401 \times 4\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 9604\) |
\(\ds 8^4 \times 2^1\) | \(=\) | \(\ds 4096 \times 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 8192\) |
So none of the above $4$-digit powers multiplied by any of these single-digit powers satisfies the condition.
We have that $\sqbrk {abcd}$ cannot end in $0$, as that can also be ruled out by inspection of the $4$-digit powers.
Similarly, because $a \ne 1$, $\sqbrk {abcd} > 2000$.
Also, it cannot be the case that both $a^b$ and $c^d$ are smaller than $44$, as $44^2 < 2000$.
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Source of Name
This entry was named for Henry Ernest Dudeney.
Historical Note
This result is generally attributed to Henry Ernest Dudeney, who stated it in his $1917$ book Amusements in Mathematics.
It continues to crop up occasionally in puzzle pages of journals.
The term Dudeney's Property of 2592 was invented by $\mathsf{Pr} \infty \mathsf{fWiki}$ as a convenient shorthand for what would otherwise be tediously unwieldy.
As such, it is not generally expected to be seen in this context outside $\mathsf{Pr} \infty \mathsf{fWiki}$.
Sources
- 1917: Henry Ernest Dudeney: Amusements in Mathematics: Various Arithmetical and Algebraical Problems: $115$. A Printer's Error
- 1933: Raphael M. Robinson: E69 (Amer. Math. Monthly Vol. 40: p. 607) www.jstor.org/stable/2301693
- 1934: C.W. Trigg: E69 (solution) (Amer. Math. Monthly Vol. 41: p. 332) www.jstor.org/stable/2301005
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $2592$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $2592$