Expectation of Product of Independent Random Variables is Product of Expectations/Corollary
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Corollary to Expectation of Product of Independent Random Variables is Product of Expectations
Let $\struct {\Omega, \Sigma, \Pr}$ be a probability space.
Let $X$ and $Y$ be integrable random variables that are independent.
Then:
- $\expect {X Y} = \expect X \expect Y$
Proof
We have:
\(\ds \expect {X Y}\) | \(=\) | \(\ds \expect {\paren {X^+ - X^-} \paren {Y^+ - Y^-} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+ Y^+ - X^+ Y^- - X^- Y^+ + X^- Y^-}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+ Y^+} - \expect {X^+ Y^-} - \expect {X^- Y^+} + \expect {X^- Y^-}\) | Expectation is Linear | |||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+} \expect {Y^+} - \expect {X^+} \expect {Y^-} - \expect {X^-} \expect {Y^+} + \expect {X^- Y^-}\) | Expectation of Product of Independent Random Variables is Product of Expectations | |||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+} \paren {\expect {Y^+} - \expect {Y^-} } - \expect {X^-} \paren {\expect {Y^+} - \expect {Y^-} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+} \expect {Y^+ - Y^-} - \expect {X^-} \expect {Y^+ - Y^-}\) | Expectation is Linear | |||||||||||
\(\ds \) | \(=\) | \(\ds \expect {X^+} \expect Y - \expect {X^-} \expect Y\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \expect Y \expect {X^+ - X^-}\) | Expectation is Linear | |||||||||||
\(\ds \) | \(=\) | \(\ds \expect X \expect Y\) |
$\blacksquare$