External Angle of Triangle equals Sum of other Internal Angles/Proof 2
Jump to navigation Jump to search
In the words of Euclid:
- In any triangle, if one of the sides be produced, the exterior angle is equal to the two interior and opposite angles, and the three interior angles of the triangle are equal to two right angles.
Let $\triangle ABC$ be a triangle.
- $\paren 1: \angle ABC + \angle BCA + \angle CAB = 180^\circ$
Extend $AB$ to $D$.
- $\paren 1: \angle ABC + \angle CBD = 180^\circ$
Combining $\paren 1$ and $\paren 2$ and using Equality is Transitive:
- $\angle ABC + \angle BCA + \angle CAB = \angle ABC + \angle CBD$
By using commom notion 3:
- $\angle BCA + \angle CAB = \angle CBD$
By using Equality is Symmetric:
- $\angle CBD = \angle BCA + \angle CAB$