Four Fours/Lemmata/Three Fours/55

Puzzle

Using exactly $3$ instances of the number $4$, the task is to write an expression for $55$, using whatever arithmetical operations you consider necessary.

Solutions

Solution $1$

$55 = \dfrac {4! - \sqrt 4} {.4}$

Solution $2$

$55 = \dfrac {4! + {. \dot 4} } {. \dot 4}$

Also see

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