Four Fours/Lemmata/Three Fours/55/Solutions/2
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Puzzle: Three Fours: $55$
Using exactly $3$ instances of the number $4$, the task is to write an expression for $55$, using whatever arithmetical operations you consider necessary.
Solution
- $55 = \dfrac {4! + {. \dot 4} } {. \dot 4}$