Henry Ernest Dudeney/Puzzles and Curious Problems/Crossing River Problem, and Problems Concerning Games and Puzzle Games
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Henry Ernest Dudeney: Puzzles and Curious Problems: Crossing River Problem, and Problems Concerning Games and Puzzle Games
$303$ - Crossing the River
- During the Turkish stampede in Thrace, a small detachment found itself confronted by a wide and deep river.
- However, they discovered a boat in which two children were rowing about.
- It was so small that it would only carry the two children, or one grown up person.
- How did the officer get himself and his $357$ soldiers across the river and leave the two children finally in joint possession of their boat?
- And how many times need the boat pass from shore to shore?
$304$ - Grasshoppers' Quadrille
- It is required to make the white men change places with the black men in the fewest possible moves.
- There is no diagonal play, nor are there captures.
- The white men can only move to the right or downwards, and the black men to the left or upwards,
- but they may leap over one of the opposite colour, as in draughts.
$305$ - Domino Frames
- Take an ordinary set of $28$ dominoes and return double $3$, double $4$, double $5$, and double $6$ to the box as not wanted.
- Now, with the remainder form three square frames, in the manner shown, so that the pips in every side shall add up alike.
- In the example given the sides sum to $15$.
- If this were to stand, the sides of the other two frames must also sum to $15$.
- But you can take any number you like, and it will be seen that it is not required to place $6$ against $6$, $5$ against $5$, and so on, as in play.
$306$ - A Puzzle in Billiards
- Alfred Addlestone can give Benjamin Bounce $20$ points in $100$, and beat him;
- Bounce can give Charlie Cruikshank $25$ points in $100$, and beat him.
- Now, how many points can Addlestone give Cruikshank in order to beat him in a game of $200$ up?
- Of course we assume that the players play constantly with the same relative skill.
$307$ - Scoring at Billiards
- What is the highest score that you can make in two consecutive shots at billiards?
$308$ - Domino Hollow Squares
- It is required with the $28$ dominoes to form $7$ hollow squares, like the example given,
- so that the pips in the four sides of every square shall add up alike.
- All these seven squares need not have the same sum, and, of course, the example given need not be one of your set.
$309$ - Domino Sequences
- A boy who had a complete set of dominoes, up to double $9$, was trying to arrange them all in sequence, in the usual way --
- $6$ against $6$, $3$ against $3$, blank against blank, and so on.
- His father said to him, "You are attempting an impossibility, but if you let me pick out $4$ dominoes it can them be done.
- And those I take shall contain the smallest total number of pips possible in the circumstances.
- Now, which dominoes might the father have selected?
$310$ - Two Domino Squares
- Arrange the $28$ dominoes as shown in the diagram to form two squares
- so that the pips in every one of the eight sides shall add up alike.
- The constant addition must of course be within limits to make the puzzle possible,
- and it will be interesting to find those limits.
- Of course, the dominoes need not be laid according to the rule, $6$ against $6$, blank against blank, and so on.
$311$ - Domino Multiplication
- Four dominoes may be so placed as to form a simple multiplication sum if we regard the pips as figures.
- The example here shown will make everything perfectly clear.
- Now, the puzzle is, using all the $28$ dominoes to arrange them so as to form $7$ such little sums in multiplication.
- No blank may be placed at the left end of the multiplicand or product.
$312$ - Domino Rectangle
- Arrange the $28$ dominoes exactly as shown in the diagram, where the pips are omitted,
- so that the pips in every one of the seven columns shall sum to $24$, and the pips in every one of the eight rows to $21$.
- The dominoes need not be $6$ against $6$, $4$ against $4$, and so on.
$313$ - The Domino Column
- Arrange the $28$ dominoes in a column so that the three sets of pips, taken anywhere,
- shall add up alike on the left side and on the right.
- Such a column has been started in the diagram.
- This is merely an example, so you can start afresh if you like.
$314$ - Card Shuffling
- The rudimentary method of shuffling a pack of cards is to take the pack face downwards in the left hand and then transfer them one by one to the right hand,
- putting the second on top of the third, the third under, the fourth above, and so on until all are transferred.
- If you do this with any even number of cards and keep on repeating the shuffle in the same way,
- the cards will in due time return to their original order.
- Try with $4$ cards, and you will find the order is restored in $3$ shuffles.
- In fact, where the number of cards is $2$, $4$, $8$, $16$, $32$, $64$,
- the number of shuffles to get them back to the original arrangement is $2$, $3$, $4$, $5$, $6$, $7$ respectively.
- Now, how many shuffles are necessary in the case of $14$ cards?
$315$ - Arranging the Dominoes
- The number of ways the set of $28$ dominoes may be arranged in a straight line, in accordance with the original rule of the game,
- left to right and right to left, in any arrangement counting as different ways,
- is $7 \, 959 \, 229 \, 931 \, 520$.
- After discarding all dominoes bearing a $5$ or a $6$, how many ways may the remaining $15$ dominoes be so arranged in a line?
$316$ - Queer Golf
- A certain links had nine holes, $300$, $250$, $200$, $325$, $275$, $350$, $225$, $375$, and $400$ yards apart.
- If a man could always strike the ball in a perfectly straight line and send it exactly one of two distances,
- so that it would either go towards the hole, pass over it, or drop into it,
- what would those two distances be that would carry him in the least number of strokes round the whole course?
- Two very good distances are $125$ and $75$, which carry you round in $28$ strokes,
- but this is not the correct answer.
$317$ - The Archery Match
- On a target on which the scoring was $40$ for the bull's-eye, and $39$, $24$, $23$, $17$ and $16$ respectively for the rings from the centre outwards, as shown in the diagram,
- three players had a match with six arrows each.
- The result was:
- Miss Dora Talbot: $120$ points;
- Reggie Watson, $110$ points;
- Mrs. Finch, $100$ points.
- Every arrow scored, and the bull's-eye was only once hit.
- Can you, from these facts, determine the exact six hits made by each competitor?
$318$ - Target Practice
- Three people in an archery competition had each had six shots at a target, and the result is shown in the diagram,
- where they all hit the target every time.
- The bull's-eye scores $50$, then the scores are $25$, $20$, $10$, $5$, $3$, $2$, $1$ for the rings from the centre outwards respectively.
- It is seen that the hits on target are $1$ bull's-eye, two $25$s, three $20$s, three $10$s, three $1$s and two hits in each of the other rings.
- The three men tied with an equal score.
- Can you work out who hit what?
$319$ - The Ten Cards
- Place any ten playing cards in a row face up.
- There are two players.
- The first player may turn face down any single card he chooses.
- Then the second player can turn face down any single card or any $2$ adjacent cards.
- And so on.
- Thus the first player must turn face down a single, but afterwards either player may turn down either a single or two adjacent cards.
- The player who turns down the last card wins.
- Should the first or second player win?