Hyperbolic Cosine Function is Even/Proof 2

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Theorem

$\map \cosh {-x} = \cosh x$


Proof

\(\ds \map \cosh {-x}\) \(=\) \(\ds \map \cos {-i x}\) Hyperbolic Cosine in terms of Cosine
\(\ds \) \(=\) \(\ds \map \cos {i x}\) Cosine Function is Even
\(\ds \) \(=\) \(\ds \cosh x\) Hyperbolic Cosine in terms of Cosine

$\blacksquare$