Integral Operator is Linear/Corollary 2
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Theorem
Let $T$ be an integral operator.
Let $f$ be an integrable real function on a domain appropriate to $T$.
Then:
- $\forall \alpha \in \R: \map T {\alpha f} = \alpha \map T f$
Proof
From Integral Operator is Linear:
- $\forall \alpha, \beta \in \R: \map T {\alpha f + \beta g} = \alpha \map T f + \beta \map T g$
The result follows by setting $\beta = 0$.
$\blacksquare$
Sources
- 1968: Peter D. Robinson: Fourier and Laplace Transforms ... (previous) ... (next): $\S 1.1$. The Idea of an Integral Transform