# Isomorphism Preserves Semigroups

## Theorem

Let $\struct {S, \circ}$ and $\struct {T, *}$ be algebraic structures.

Let $\phi: S \to T$ be an isomorphism.

If $\struct {S, \circ}$ is a semigroup, then so is $\struct {T, *}$.

## Proof 1

If $\left({S, \circ}\right)$ is a semigroup, then by definition it is closed.

From Morphism Property Preserves Closure, $\left({T, *}\right)$ is therefore also closed.

If $\left({S, \circ}\right)$ is a semigroup, then by definition $\circ$ is associative.

From Isomorphism Preserves Associativity, $*$ is therefore also associative.

So $\left({T, *}\right)$ is closed, and $*$ is associative, and therefore by definition, $\left({T, *}\right)$ is a semigroup.

$\blacksquare$

## Proof 2

An isomorphism is an epimorphism.

The result follows as a direct corollary of Epimorphism Preserves Semigroups.

$\blacksquare$