Kuratowski's Closure-Complement Problem/Closure of Complement
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Theorem
Let $\R$ be the real number line with the usual (Euclidean) topology.
Let $A \subseteq \R$ be defined as:
\(\ds A\) | \(:=\) | \(\ds \openint 0 1 \cup \openint 1 2\) | Definition of Union of Adjacent Open Intervals | |||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \set 3\) | Definition of Singleton | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \paren {\Q \cap \openint 4 5}\) | Rational Numbers from $4$ to $5$ (not inclusive) |
The closure of the complement of $A$ in $\R$ is given by:
\(\ds A^{\prime \, -}\) | \(=\) | \(\ds \hointl \gets 0\) | Definition of Unbounded Closed Real Interval | |||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \set 1\) | Definition of Singleton | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \hointr 2 \to\) | Definition of Unbounded Closed Real Interval |
Proof
From Kuratowski's Closure-Complement Problem: Complement:
\(\ds A'\) | \(=\) | \(\ds \hointl \gets 0\) | Definition of Unbounded Closed Real Interval | |||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \set 1\) | Definition of Singleton | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \hointr 2 3\) | Definition of Half-Open Real Interval | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \hointl 3 4\) | adjacent to Half-Open Real Interval | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \paren {\R \setminus \Q \cap \closedint 4 5}\) | Irrational Numbers from $4$ to $5$ | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \hointr 5 \to\) | Definition of Unbounded Closed Real Interval |
From Real Number is Closed in Real Number Line:
- $\set 3$ is closed in $\R$
and:
- $\hointl \gets 0$ is closed in $\R$
and:
- $\hointr 5 \to$ is closed in $\R$
Then from Set is Closed iff Equals Topological Closure:
- $\set 3^- = \set 3$
- $\hointl \gets 0^- = \hointl \gets 0$
- $\hointr 5 \to^- = \hointr 5 \to$
From Closure of Half-Open Real Interval is Closed Real Interval:
- $\hointr 2 3 = \closedint 2 3$
and:
- $\hointl 3 4 = \closedint 3 4$
From Closure of Irrational Interval is Closed Real Interval:
- $\paren {\R \setminus \Q \cap \closedint 4 5}^- = \closedint 4 5$
From Closure of Finite Union equals Union of Closures:
\(\ds A^{\prime \, -}\) | \(=\) | \(\ds \hointl \gets 0\) | Definition of Unbounded Closed Real Interval | |||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \set 1\) | Definition of Singleton | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \closedint 2 3\) | Definition of Closed Real Interval | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \closedint 3 4\) | Definition of Closed Real Interval | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \closedint 4 5\) | Definition of Closed Real Interval | ||||||||||
\(\ds \) | \(\) | \(\, \ds \cup \, \) | \(\ds \hointr 5 \to\) | Definition of Unbounded Closed Real Interval |
The result follows.
$\blacksquare$