Linear First Order ODE/y' + (y over x) = 3 x
Jump to navigation
Jump to search
Theorem
- $\dfrac {\d y} {\d x} + \dfrac y x = 3 x$
has the general solution:
- $x y = x^3 + C$
or:
- $y = x^2 + \dfrac C x$
Proof
This is a special case of:
where $k = 3$ and $n = 1$, yielding:
- $y = x^2 + \dfrac C x$
Multiplying through by $x$ reveals:
- $x y = x^3 + C$
$\blacksquare$
Sources
- 1972: George F. Simmons: Differential Equations ... (previous) ... (next): $\S 2.10$: Example $1$