Magma is Submagma of Itself

Theorem

Let $\struct {S, \circ}$ be a magma.

Then $\struct {S, \circ}$ is a submagma of itself.

Proof

By definition, a magma is an algebraic structure $\struct {S, \circ}$ where $\circ$ is closed.

That is:

$\forall x, y \in S: x \circ y \in S$

From Set is Subset of Itself, $S \subseteq S$.

By definition, $\struct {T, \circ}$ is a submagma of $S$ if:

$\forall x, y \in T: x \circ y \in T$

It follows from the above that $\struct {S, \circ}$ is, by definition, a submagma of itself.

$\blacksquare$

Sources

• 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {II}$: New Structures from Old: $\S 8$: Compositions Induced on Subsets: Example $8.3$