Open Ray is Open in GO-Space/Definition 2
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Theorem
Let $\struct {S, \preceq, \tau}$ be a generalized ordered space by Definition 2.
That is:
- Let $\struct {S, \preceq}$ be a totally ordered set.
- Let $\struct {S, \tau}$ be a topological space.
Let there be:
- a linearly ordered space $\struct {S', \preceq', \tau'}$
and:
- a mapping $\phi: S \to S'$ which is both:
- a $\preceq$-$\preceq'$ order embedding
- and:
- a $\tau$-$\tau'$ topological embedding.
Let $p \in S$.
Then:
- $p^\prec$ and $p^\succ$ are $\tau$-open
where:
- $p^\prec$ is the strict lower closure of $p$
- $p^\succ$ is the strict upper closure of $p$.
Proof
We will prove that $p^\succ$ is open.
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That $p^\prec$ is open will follow by duality.
By Inverse Image under Order Embedding of Strict Upper Closure of Image of Point:
- $\map {\phi^{-1} } {\map \phi p^\succ} = p^\succ$
- $\map \phi p^\succ$ is an open ray in $S'$
Therefore $\tau'$-open by the definition of the order topology.
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Since $\phi$ is a topological embedding, it is continuous.
Thus $p^\succ$ is $\tau$-open.
$\blacksquare$