Order Generating iff Every Superset Closed on Infima is Whole Space

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $L = \struct {S, \vee, \wedge, \preceq}$ be a complete lattice.

Let $X$ be a subset of $S$.


Then

$X$ is order generating

if and only if

$\forall Y \subseteq S: Y \supseteq X \land \paren {\forall Z \subseteq Y: \inf Z \in Y} \implies Y = S$


Proof

Sufficient Condition

Let $X$ be order generating.

Let $Y \subseteq S$ such that

$Y \supseteq X \land \paren {\forall Z \subseteq Y: \inf Z \in Y}$

We will prove that

$S \subseteq Y$

Let $s \in S$.

By Order Generating iff Every Element is Infimum:

$\exists Z \subseteq X: s = \inf Z$

By Subset Relation is Transitive:

$Z \subseteq Y$

Thus by assumption:

$s \in Y$

$\Box$


By definition of set equality:

$Y = S$

$\Box$


Necessary Condition

Assume that:

$\forall Y \subseteq S: Y \supseteq X \land \paren {\forall Z \subseteq Y: \inf Z \in Y} \implies Y = S$

Define $Y := \set {\inf Z: Z \subseteq X}$

By definition of subset:

$Y \subseteq S$

We will prove that

$X \subseteq Y$

Let $x \in X$.

By definitions of singleton and subset:

$\set x \subseteq X$

By Infimum of Singleton:

$\inf \set x = x$

Thus by definition of $Y$:

$x \in Y$

$\Box$


We will prove that:

$\forall x \in S: \exists Z \subseteq X: x = \inf Z$

Let $x \in S$.

We will prove that:

$\forall Z \subseteq Y: \inf Z \in Y$

Let $Z \subseteq Y$.

Define:

$T := \bigcup \set {A \subseteq X: \inf A \in Z}$

By Union of Subsets is Subset:

$T \subseteq X \subseteq S$

Define:

$N := \set {\inf A: A \subseteq X \land \inf A \in Z}$

We will prove that:

$Z \subseteq N$

Let $y \in Z$.

By definition of subset:

$y \in Y$

By definition of $Y$:

$\exists Z \subseteq X: y = \inf Z$

Thus by definition of $N$:

$y \in N$

$\Box$


By definition of subset:

$N \subseteq Z$

By definition of set equality:

$Z = N$

By Infimum of Infima:

$\inf Z = \inf T$

Thus

$\inf Z \in Y$

$\Box$


By assumption:

$Y = S$

Then

$x \in Y$

Thus by definition of $Y$:

$\exists Z \subseteq X: x = \inf Z$

$\Box$


Hence $X$ is order generating by Order Generating iff Every Element is Infimum.

$\blacksquare$


Sources