Orthogonal Trajectories of One-Parameter Family of Curves

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Theorem

Every one-parameter family of curves has a unique family of orthogonal trajectories.


Proof

Let $\map f {x, y, z}$ define a one-parameter family of curves $\FF$.

From One-Parameter Family of Curves for First Order ODE‎, there is a corresponding first order ODE:

$\map F {x, y, \dfrac {\d y} {\d x} }$

whose solution is $\FF$.


From Slope of Orthogonal Curves, the slope of one curve is the negative reciprocal of any curve orthogonal to it.

So take the equation:

$\map F {x, y, \dfrac {\d y} {\d x} }$

and from it create the equation:

$\map F {x, y, -\dfrac {\d x} {\d y} }$

that is, replace $\dfrac {\d y} {\d x}$ with $-\dfrac {\d x} {\d y}$.

This is also a first order ODE, which corresponds with a one-parameter family of curves $\GG$ defined by the implicit function $\map f {x, y, z}$.


There is clearly one way of doing the above.

Hence the result.

$\blacksquare$


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