Period of Revolution of Conical Pendulum

Theorem

Let $P$ be a conical pendulum.

Let $h$ be the height of the pivot of $P$ above the circle in which $P$ is moving.

Then the period of revolution of $P$ around the circle is given by:

$T = 2 \pi \sqrt {\dfrac h g}$

where $g$ is the acceleration on $P$ caused by the gravitational field in which $P$ is suspended.

Proof

This theorem requires a proof. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code. If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page.

Sources

• 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): conical pendulum
• 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): conical pendulum