Pointwise Operation on Distributive Structure is Distributive
Theorem
Let $S$ be a set.
Let $\struct {T, +, \circ}$ be an algebraic structure with two operations $+$ and $\circ$.
Let $T^S$ be the set of all mappings from $S$ to $T$.
Let $\struct {T^S, +', \circ'}$ be the structure induced on $T^S$ by $+$ and $\circ$.
Let $\circ$ be distributive over $+$ in $T$.
Then $\circ'$ is distributive over $+'$ in $T$.
Proof
Let $f, g, h: S \to T$ be elements of $T^S$.
Suppose $S$ is the empty set.
Suppose $T^S$ is the set of all mappings from the empty set, $S$, to $T$.
Suppose $\struct {T^S, +', \circ'}$ is the structure induced on $T^S$ by $+$ and $\circ$.
Suppose $\circ$ is distributive over $+$ in $T$.
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Then $\circ'$ is distributive over $+'$ in $T$, as required.
Suppose $S$ is non-empty.
Let $x \in S$.
Then:
\(\ds \map {\paren {f \circ' \paren {g +' h} } } x\) | \(=\) | \(\ds \map f x \circ \paren {\map g x + \map h x}\) | Definition of Induced Structure | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\map f x \circ \map g x} + \paren {\map f x \circ \map h x}\) | $\circ$ is distributive over $+$ on $T$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {\paren {\paren {f \circ' g} +' \paren {f \circ' h} } } x\) | Definition of Induced Structure |
Similarly:
- $\map {\paren {\paren {g +' h} \circ' f} } x = \map {\paren {\paren {g \circ' f} +' \paren {h \circ' f} } } x$
Hence the result.
$\blacksquare$