# Pointwise Sum of Measurable Functions is Measurable

## Theorem

Let $\left({X, \Sigma}\right)$ be a measurable space.

Let $f, g: X \to \overline{\R}$ be $\Sigma$-measurable functions.

Assume that the pointwise sum $f + g: X \to \overline{\R}$ is well-defined.

Then $f + g$ is a $\Sigma$-measurable function.

## Proof

By Measurable Function Pointwise Limit of Simple Functions, we find sequences $\left({f_n}\right)_{n \in \N}, \left({g_n}\right)_{n \in \N}$ such that:

- $\displaystyle f = \lim_{n \to \infty} f_n$
- $\displaystyle g = \lim_{n \to \infty} g_n$

where the limits are pointwise.

It follows that for all $x \in X$:

- $f \left({x}\right) + g \left({x}\right) = \displaystyle \lim_{n \to \infty} f_n \left({x}\right) + g_n \left({x}\right)$

so that we have the pointwise limit:

- $\displaystyle f + g = \lim_{n \to \infty} f_n + g_n$

By Pointwise Sum of Simple Functions is Simple Function, $f + g$ is a pointwise limit of simple functions.

By Simple Function is Measurable, $f + g$ is a pointwise limit of measurable functions.

Hence $f + g$ is measurable, by Pointwise Limit of Measurable Functions is Measurable.

$\blacksquare$

## Sources

- 2005: René L. Schilling:
*Measures, Integrals and Martingales*... (previous) ... (next): $8.10$