Primitive of Reciprocal of 1 minus Sine of a x/Corollary 1

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Theorem

$\ds \int \frac {\d x} {1 - \sin x} = \map \tan {\frac x 2 + \frac \pi 4} + C$


Proof

\(\ds \int \frac {\d x} {1 - \sin a x}\) \(=\) \(\ds \frac 1 a \map \tan {\frac \pi 4 + \frac {a x} 2} + C\) Primitive of $\dfrac 1 {1 - \sin a x}$
\(\ds \leadsto \ \ \) \(\ds \int \frac {\d x} {1 - \sin x}\) \(=\) \(\ds \map \tan {\frac \pi 4 + \frac x 2} + C\) setting $a \gets 1$
\(\ds \) \(=\) \(\ds \map \tan {\frac x 2 + \frac \pi 4} + C\) rearranging

$\blacksquare$


Sources