Quaternion Modulus of Product of Quaternions
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Theorem
Let $\mathbf x, \mathbf y$ be quaternions.
Let $\size {\mathbf x}$ be the modulus of $\mathbf x$.
Then:
- $\size {\mathbf {x y} } = \size {\mathbf x} \size {\mathbf y}$
Proof
Let $\mathbf x, \mathbf y$ be in their matrix form.
Then:
\(\ds \size {\mathbf {x y} }\) | \(=\) | \(\ds \sqrt {\map \det {\mathbf {x y} } }\) | Definition of Quaternion Modulus | |||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt {\map \det {\mathbf x} \map \det {\mathbf y} }\) | Determinant of Matrix Product | |||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt {\map \det {\mathbf x} } \sqrt {\map \det {\mathbf y} }\) | Exponent Combination Laws | |||||||||||
\(\ds \) | \(=\) | \(\ds \size {\mathbf x} \size {\mathbf y}\) | Definition of Quaternion Modulus |
$\blacksquare$