Set Equivalence behaves like Equivalence Relation/Symmetric

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Theorem

Set equivalence behaves like a symmetric relation:

$S \sim T \implies T \sim S$


Proof

\(\ds \) \(\) \(\ds S \sim T\)
\(\ds \) \(\leadsto\) \(\ds \exists \phi: S \to T\) Definition of Set Equivalence, where $\phi$ is a bijection
\(\ds \) \(\leadsto\) \(\ds \exists \phi^{-1}: T \to S\) Bijection iff Inverse is Bijection
\(\ds \) \(\leadsto\) \(\ds T \sim S\) Definition of Set Equivalence: $\phi^{-1}$ is also a bijection

$\blacksquare$


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