Smallest Fourth Power as Sum of 5 Distinct Fourth Powers
Theorem
The smallest $4$th power which can be expressed as the sum of $5$ distinct $4$th powers is:
- $15^4 = 4^4 + 6^4 + 8^4 + 9^4 + 14^4$
Proof
\(\ds 15^4\) | \(=\) | \(\ds 50 \, 625\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 256 + 1296 + 4096 + 6561 + 38 \, 416\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 4^4 + 6^4 + 8^4 + 9^4 + 14^4\) |
By Fermat's Little Theorem, for $5 \nmid a$:
- $a^4 \equiv 1 \pmod 5$
For $5 \divides a$:
- $a^4 \equiv 0 \pmod 5$
Therefore in order for the equality to hold, one of the following must be true:
- The $4$th power on the right hand side is not divisible by $5$, while exactly $1$ of the $5$ $4$th powers on the left hand side is not divisible by $5$
- The $4$th power on the right hand side is divisible by $5$, while all of the $5$ $4$th powers on the left hand side is divisible by $5$
- The $4$th power on the right hand side is divisible by $5$, while none of the $5$ $4$th powers on the left hand side is divisible by $5$.
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In the first two cases, there must be at least $4$ distinct $4$th powers divisible by $5$.
The smallest multiples of $5$ are $0, 5, 10, 15$.
Hence the $4$th powers on the left hand side must exceed $15^4$.
Thus these cases cannot produce a smaller example.
This leaves us with the third case, where left hand side is divisible by $5$.
Since $5^4 \ne 4^4 + 3^4 + 2^4 + 1^4 + 0^4$, we only need to check that $10^4$ is not a sum of $5$ distinct $4$th powers.
As $8^4 + 7^4 + 6^4 + 5^4 + 4^4 = 8674 < 10^4$, we must have $9^4$ on the right hand side.
As $9^4 + 8^4 = 10657 > 10^4$, we cannot have $8^4$ on the right hand side.
As $9^4 + 6^4 + 5^4 + 4^4 + 3^4 = 8819 < 10^4$, we must have $7^4$ on the right hand side.
As $9^4 + 7^4 + 6^4 = 10258 > 10^4$, we cannot have $6^4$ on the right hand side.
But $9^4 + 7^4 + 5^4 + 4^4 + 3^4 = 9924 < 10^4$.
Therefore $10^4$ is not a sum of $5$ distinct $4$th powers.
This proves that $15^4$ is the smallest $4$th power which can be expressed as the sum of $5$ distinct $4$th powers.
$\blacksquare$
Also see
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $50,625$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $50,625$