Smallest Number with 2^n Divisors/Mistake
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Source Work
1986: David Wells: Curious and Interesting Numbers:
- The Dictionary
- $120$
Mistake
- The smallest number having $2^n$ divisors is found by multiplying together the first $n$ numbers in this sequence: $2$, $3$, $4$, $5$, $7$, $9$, $11$, $13$, $16$, $17$, $19$, $\ldots$ which consists of all the primes and powers of primes.
Correction
The last clause should say:
- ... which consists of all the numbers of the form $p^{\paren {2^k} }$ where $p$ is prime and $k \ge 0$.
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $120$