Speed of Hour Hand

Theorem

Consider an analogue clock $C$.

The hour hand of $C$ rotates at $\dfrac 1 2$ of a degree per minute.

Proof

It takes $12$ hours, for the hour hand to go round the dial one time.

That is, in $12$ minutes the hour hand travels $360 \degrees$.

So in $1$ hour, the hour hand travels $\dfrac {360} {12} \degrees$, that is, $30 \degrees$.

So in $1$ minute, the hour hand travels $\dfrac 1 {60} \times 30 \degrees$, that is, $\dfrac 1 2 \degrees$.

$\blacksquare$

Also see

• Speed of Minute Hand