Stabilizer of Element of Group Acting on Itself is Trivial
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Theorem
Let $\struct {G, \circ}$ be a group whose identity is $e$.
Let $*$ be the group action of $\struct {G, \circ}$ on itself by the rule:
- $\forall g, h \in G: g * h = g \circ h$
Then the stabilizer of an element $x \in G$ is given by:
- $\Stab x = \set e$
Proof
Let $g \in \Stab x$.
Then:
\(\ds g * x\) | \(=\) | \(\ds x\) | Definition of Stabilizer | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds g \circ x\) | \(=\) | \(\ds x\) | Definition of Group Action (this particular one) | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds g\) | \(=\) | \(\ds e\) | Definition of Identity Element |
Hence the result, by definition of trivial subgroup.
$\blacksquare$
Also see
Sources
- 1996: John F. Humphreys: A Course in Group Theory ... (previous) ... (next): Chapter $10$: The Orbit-Stabiliser Theorem: Example $10.10$