Sum of Summations over Overlapping Domains/Proof

Theorem

$\ds \sum_{\map R j} a_j + \sum_{\map S j} a_j = \sum_{\map R j \mathop \lor \map S j} a_j + \sum_{\map R j \mathop \land \map S j} a_j$

where $\lor$ and $\land$ signify logical disjunction and logical conjunction respectively.

$\ds \sum_{\map R j} a_j + \sum_{\map S j} a_j$

$=$

$\ds \sum_{j \mathop \in \Z} a_j \sqbrk {\map R j} + \sum_{j \mathop \in \Z} a_j \sqbrk {\map R j}$

$\ds $

$=$

$\ds \sum_{j \mathop \in \Z} a_j \paren {\sqbrk {\map R j} + \sqbrk {\map R j} }$

Let:

$A := \set {j \in \Z: \map R j}$

$B := \set {j \in \Z: \map R j}$

The result then follows from Cardinality of Set Union.

$\blacksquare$