Talk:Complement of Bounded Set has Exactly One Unbounded Component

I have a feeling that the spirit of your proof transfers to infinite-dimensional NVSs as well. Thanks for doing this anyway, I will need it. Caliburn (talk) 19:49, 11 October 2023 (UTC)

It would be easier if we already had that the $n$-sphere was connected (for $n \ge 1$). I might redlink that for now. It should probably be on a separate page anyway. --CircuitCraft (talk) 22:27, 11 October 2023 (UTC)