Talk:Cubes which are Sum of Five Cubes

The page in Wells says just:

Since $6^3 = 3^3 + 4^3 + 5^3$, $9^3$ is also the sum of $5$ cubes.

The fact that this is not a particularly profound result, as in that all numbers greater than $8$ can be expressed as the sum of $5$ cubes (I hadn't noticed that fact myself when I wrote it), I'm not sure where to go with this page.

Any ideas? --prime mover (talk) 08:24, 8 August 2020 (UTC)

My thoughts are:

modify it to the style of Twelve Factorial plus One is divisible by 13 Squared

or preferably add it as a footnote in 729

We don't do footnotes as such in $\mathsf{Pr} \infty \mathsf{fWiki}$, if we can help it -- too messy to maintain easily. The first option looks best. --prime mover (talk) 21:52, 8 August 2020 (UTC)

I do not know whether the sum of $5$ cubes result is proven, it's just highly probable, as are all Waring-type problems. --RandomUndergrad (talk) 13:28, 8 August 2020 (UTC)

In that case, unless we raise it as a separate page in the existing Waring suite of pages, we would do well to leave it alone, until we find a reliable source to use as base material. --prime mover (talk) 21:52, 8 August 2020 (UTC)