Talk:Pi Squared is Irrational/Proof 2

The proof has several errors - one is here:

Let us define a polynomial:

$\ds \map f x = \frac {\paren {1 - x^2}^n} {n!} = \sum_{m \mathop = n}^{2 n} \frac {c_m} {n!} x^m$

for $c_m \in \Z$.

If $n = 1$

\(\ds \map f x\)

\(=\)

\(\ds \frac {\paren {1 - x^2} } {1!}\)

$n = 1$

\(\ds \sum_{m \mathop = n}^{2 n} \frac {c_m} {n!} x^m\)

\(=\)

\(\ds \sum_{m \mathop = 1}^2 \frac {c_m} {1!} x^m\)

\(\ds \)

\(=\)

\(\ds c_1 x + c_2 x^2\)

This would correct the issue:

$\ds \map f x = \frac {\paren {1 - x^2}^n} {n!} = \sum_{m \mathop = 0}^n \frac {c_m} {n!} x^{2 m}$

for $c_m \in \Z$.

There are additional errors similar to this one. --Robkahn131 (talk) 21:39, 16 April 2024 (UTC)

Thx Rob, I suspected as much. Please feel free to either fix them or to put an instance of {{Mistake}} or {{Questionable}} template in place for each one. --prime mover (talk) 22:58, 16 April 2024 (UTC)