User:Dfeuer/Principle of Recursive Definition/Peano Numbers
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Theorem
Let $\N$ be a class satisfying Peano's axioms.
Let $F: A \to A$ be a mapping.
Let $a \in A$.
Then there is a unique mapping $G: \N \to A$ such that:
- $\map G 0 = a$
- $\forall n \in \N: \map G {n^+} = \map F {\map G n}$
Proof
Finite Sections
For each $n \in \N$, there is a unique mapping $g_n: \N_n \to A$ such that: