Brahmagupta-Fibonacci Identity/General/Corollary

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Corollary to General Version of Brahmagupta-Fibonacci Identity

Let $a, b, c, d, n$ be numbers.

Then:

$\paren {a^2 + n b^2} \paren {c^2 + n d^2} = \paren {a c - n b d}^2 + n \paren {a d + b c}^2$


Proof

\(\ds \paren {a^2 + n b^2} \paren {c^2 + n d^2}\) \(=\) \(\ds \paren {a c + n b d}^2 + n \paren {a d - b c}^2\) General Version of Brahmagupta-Fibonacci Identity
\(\ds \leadsto \ \ \) \(\ds \paren {a^2 + n \paren {-b}^2} \paren {c^2 + n d^2}\) \(=\) \(\ds \paren {a c + n \paren {-b} d}^2 + n \paren {a d - \paren {-b} c}^2\) substituting $-b$ for $b$
\(\ds \leadsto \ \ \) \(\ds \paren {a^2 + n b^2} \paren {c^2 + n d^2}\) \(=\) \(\ds \paren {a c - n b d}^2 + n \paren {a d + b c}^2\)

$\blacksquare$


Source of Name

This entry was named for Brahmagupta‎ and Leonardo Fibonacci‎‎.