Definition:Bounded Mapping

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This page is about mappings which are bounded. For other uses, see Definition:Bounded.

Definition

Let $\left({T, \preceq}\right)$ be an ordered set.

Let $f: S \to T$ be a mapping.

Let the image of $f$ be bounded.


Then $f$ is bounded.


That is, $f$ is bounded if and only if it is both bounded above and bounded below.


Real-Valued Function

$f$ is bounded on $S$ if and only if:

$f$ is bounded above on $S$

and also:

$f$ is bounded below on $S$.


Complex-Valued Function

Let $f: S \to \C$ be a complex-valued function.


Then $f$ is bounded if and only if the real-valued function $\cmod f: S \to \R$ is bounded, where $\cmod f$ is the modulus of $f$.


That is, $f$ is bounded if there is a constant $K \ge 0$ such that $\cmod {f \paren z} \le K$ for all $z \in S$.


Normed Division Ring

Let $\struct {R, \norm {\,\cdot\,}}$ be a normed division ring.

Let $f: S \to R$ be a mapping from $S$ into $R$.

Then $f$ is bounded if and only if the real-valued function $\norm {\,\cdot\,} \circ f: S \to \R$ is bounded, where $\norm {\,\cdot\,} \circ f$ is the composite of $\norm {\,\cdot\,}$ and $f$.


That is, $f$ is bounded if there is a constant $K \in \R_{\ge 0}$ such that $\norm{f \paren {s}} \le K$ for all $s \in S$.


Metric Space

Let $M$ be a metric space.

Let $f: X \to M$ be a mapping from any set $X$ into $M$.


Then $f$ is a bounded mapping if and only if $f \left({X}\right)$ is bounded in $M$.


Unbounded Mapping

$f$ is unbounded if it is not bounded.