Definition:Bounded Mapping
This page is about Bounded in the context of Mapping. For other uses, see Bounded.
Definition
Let $S$ be a set.
Let $\struct {T, \preceq}$ be an ordered set.
Let $f: S \to T$ be a mapping.
Let the image of $f$ be bounded.
Then $f$ is bounded.
That is, $f$ is bounded if and only if it is both bounded above and bounded below.
Real-Valued Function
$f$ is bounded on $S$ if and only if:
- $f$ is bounded above on $S$
and also:
- $f$ is bounded below on $S$.
Complex-Valued Function
Let $f: S \to \C$ be a complex-valued function.
Then $f$ is bounded if and only if the real-valued function $\cmod f: S \to \R$ is bounded, where $\cmod f$ is the modulus of $f$.
That is, $f$ is bounded if there is a constant $K \ge 0$ such that $\cmod {\map f z} \le K$ for all $z \in S$.
Normed Division Ring
Let $\struct {R, \norm {\,\cdot\,}}$ be a normed division ring.
Let $f: S \to R$ be a mapping from $S$ into $R$.
Then $f$ is bounded if and only if the real-valued function $\norm {\,\cdot\,} \circ f: S \to \R$ is bounded, where $\norm {\,\cdot\,} \circ f$ is the composite of $\norm {\,\cdot\,}$ and $f$.
That is, $f$ is bounded if there is a constant $K \in \R_{\ge 0}$ such that $\norm{f \paren {s}} \le K$ for all $s \in S$.
Metric Space
Let $M$ be a metric space.
Let $f: X \to M$ be a mapping from any set $X$ into $M$.
Then $f$ is a bounded mapping if and only if $f \sqbrk X$ is bounded in $M$.
Normed Vector Space
Let $\struct {R, \norm {\, \cdot \,} }$ be a normed division ring.
Let $\struct {X, \norm {\, \cdot \,} }$ be a normed vector space over $R$.
Let $S$ be a set.
Let $f : S \to X$ be a mapping.
We say that $f$ is bounded if and only if there exists a real number $M > 0$ such that:
- $\norm {\map f x} \le M$ for each $x \in S$.
Unbounded Mapping
Let $\struct {T, \preceq}$ be an ordered set.
Let $f: S \to T$ be a mapping.
$f$ is unbounded if and only if $f$ is not bounded.
That is, if and only if $f$ is either unbounded above or unbounded below, or both.
Also see
- Results about bounded mappings can be found here.