Equivalence of Definitions of Real Hyperbolic Cotangent
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Theorem
The following definitions of the concept of Real Hyperbolic Cotangent are equivalent:
Definition 1
The real hyperbolic cotangent function is defined on the real numbers as:
- $\coth: \R_{\ne 0} \to \R$:
- $\forall x \in \R_{\ne 0}: \coth x := \dfrac {e^x + e^{-x} } {e^x - e^{-x} }$
where it is noted that at $x = 0$:
- $e^x - e^{-x} = 0$
and so $\coth x$ is not defined at that point.
Definition 2
The real hyperbolic cotangent function is defined on the real numbers as:
- $\coth: \R_{\ne 0} \to \R$:
- $\forall x \in \R_{\ne 0}: \coth x := \dfrac {\cosh x} {\sinh x}$
where:
- $\sinh$ is the real hyperbolic sine
- $\cosh$ is the real hyperbolic cosine
It is noted that at $x = 0$ we have that $\sinh x = 0$, and so $\coth x$ is not defined at that point.
Definition 3
The real hyperbolic cotangent function is defined on the real numbers as:
- $\coth: \R_{\ne 0} \to \R$:
- $\forall x \in \R_{\ne 0}: \coth x := \dfrac 1 {\tanh x}$
where $\tanh$ is the real hyperbolic tangent.
It is noted that at $x = 0$ we have that $\tanh x = 0$, and so $\coth x$ is not defined at that point.
Proof
\(\ds \coth x\) | \(=\) | \(\ds \dfrac {\cosh x} {\sinh x}\) | Definition 2 of Real Hyperbolic Cotangent | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\paren {\dfrac {e^x - e^{-x} } 2} } {\paren {\dfrac {e^x + e^{-x} } 2} }\) | Definition of Real Hyperbolic Sine, Definition of Real Hyperbolic Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {e^x + e^{-x} } {e^x - e^{-x} }\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds \coth x\) | Definition 1 of Real Hyperbolic Cotangent |
$\Box$
\(\ds \coth x\) | \(=\) | \(\ds \dfrac {\cosh x} {\sinh x}\) | Definition 2 of Real Hyperbolic Cotangent | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {\paren {\dfrac {\sinh x} {\cosh x} } }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {\tanh x}\) | Definition 2 of Real Hyperbolic Tangent | |||||||||||
\(\ds \) | \(=\) | \(\ds \coth x\) | Definition 3 of Real Hyperbolic Cotangent |
$\blacksquare$