Existence of Upper Bound of Finite Subset of Directed Set

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Theorem

Let $\struct {\Lambda, \preceq}$ be a directed set.

Let $\FF \subseteq \Lambda$ be a finite subset.


Then $\FF$ has an upper bound in $\struct {\Lambda, \preceq}$.


Proof

We induct on the cardinality of $\FF$.

Let $n \in \Z_{\ge 0}$.

For all $m \in \Z_{\ge 0}$, let $\map P n$ be the proposition:

if $\FF \subseteq \Lambda$ has $\card \FF = n$, then $\FF$ has an upper bound.


Basis for the Induction

The case $n = 0$ is vacuously true.

If $n = 1$ and $\FF = \set \lambda$, $\lambda$ is clearly an upper bound for $\FF$ in $\struct {\Lambda, \preceq}$.

This is our basis for the induction.


Induction Hypothesis

Now we need to show that, if $\map P k$ is true, where $k \ge 2$, then it logically follows that $\map P {k + 1}$ is true.

So this is our induction hypothesis:

if $\FF \subseteq \Lambda$ has $\card \FF = k$, then $\FF$ has an upper bound.

Then we need to show:

if $\FF \subseteq \Lambda$ has $\card \FF = k + 1$, then $\FF$ has an upper bound.


Induction Step

This is our induction step.

Let $\FF = \set {\lambda_1, \ldots, \lambda_{k + 1} }$.

Then $\GG = \set {\lambda_1, \ldots, \lambda_k}$ has $\card \GG = k$, and so there exists $\lambda \in \Lambda$ such that:

$\lambda_i \preceq \lambda$ for each $1 \le i \le n$.

From the definition of a directed set, there exists $\lambda_\ast \in \Lambda$ such that:

$\lambda \preceq \lambda_\ast$

and:

$\lambda_{k + 1} \preceq \lambda_\ast$

Then we have, from transitivity:

$\lambda_i \preceq \lambda_\ast$ for each $1 \le i \le k + 1$.

$\blacksquare$