Group Homomorphism/Examples/Pointwise Addition on Continuous Real Functions on Closed Unit Interval/Example 2
Example of Group Homomorphism
Let $J \subseteq \R$ denote the closed unit interval $\closedint 0 1$.
Let $\map {\mathscr C} J$ denote the set of all continuous real functions from $J$ to $\R$.
Let $G = \struct {\map {\mathscr C} J, +}$ be the group formed on $\map {\mathscr C} J$ by pointwise addition.
Let $\struct {\R, +}$ denote the additive group of real numbers.
From Pointwise Addition on Continuous Real Functions on Closed Unit Interval forms Group we have that $G$ is indeed a group.
Let $\phi: \struct {\map {\mathscr C} J, +} \to \struct {\R, +}$ be the mapping defined as:
- $\forall f \in \map {\mathscr C} J: \map \phi f = \size {\map f 0}$
where $\size {\, \cdot \,}$ denotes the absolute value function.
Then $\phi$ is not a homomorphism.
Proof
Let $f, g \in \map {\mathscr C} J$ be such that:
\(\ds \forall x \in J: \, \) | \(\ds \map f x\) | \(=\) | \(\ds 1\) | |||||||||||
\(\ds \forall x \in J: \, \) | \(\ds \map g x\) | \(=\) | \(\ds -1\) |
By Constant Real Function is Continuous, both $f$ and $g$ are continuous on $J$.
We have:
\(\ds \map \phi {f + g}\) | \(=\) | \(\ds \size {\map {\paren {f + g} } 0}\) | Definition of $\phi$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \size {\map f 0 + \map g 0}\) | Definition of Pointwise Addition of Real-Valued Functions | |||||||||||
\(\ds \) | \(=\) | \(\ds \size {1 + \paren {-1} }\) | Definition of $f$ and $g$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \size 0\) | arithmetic | |||||||||||
\(\ds \) | \(=\) | \(\ds 0\) | Definition of Absolute Value |
However:
\(\ds \map \phi f + \map \phi g\) | \(=\) | \(\ds \size {\map f 0} + \size {\map g 0}\) | Definition of $\phi$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \size 1 + \size {-1}\) | Definition of $f$ and $g$ | |||||||||||
\(\ds \) | \(=\) | \(\ds 1 + 1\) | Definition of Absolute Value | |||||||||||
\(\ds \) | \(=\) | \(\ds 2\) | arithmetic |
Thus:
- $\map \phi {f + g} \ne \map \phi f + \map \phi g$
and so $\phi$ is not a homomorphism by definition.
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {II}$: New Structures from Old: $\S 13$: Compositions Induced on Cartesian Products and Function Spaces: Exercise $13.18 \ \text {(b)}$