Half Angle Formula for Tangent/Corollary 2/Proof 2

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Theorem

$\tan \dfrac \theta 2 = \dfrac {1 - \cos \theta} {\sin \theta}$


Proof

\(\ds \tan \frac \theta 2\) \(=\) \(\ds \frac {\sin \frac \theta 2} {\cos \frac \theta 2}\) Definition of Real Tangent Function
\(\ds \) \(=\) \(\ds \frac {\sin \frac \theta 2} {\cos \frac \theta 2} \frac {2 \sin \frac \theta 2} {2 \sin \frac \theta 2}\) multiplying both numerator and denominator by $\dfrac {2 \sin \frac \theta 2} {2 \sin \frac \theta 2}$
\(\ds \) \(=\) \(\ds \frac {2 \sin^2 \frac \theta 2} {2 \sin \frac \theta 2 \cos \frac \theta 2}\)
\(\ds \) \(=\) \(\ds \frac {1 - \cos \theta} {2 \sin \frac \theta 2 \cos \frac \theta 2}\) Double Angle Formula for Cosine: Corollary $5$
\(\ds \) \(=\) \(\ds \frac {1 - \cos \theta} {\sin \theta}\) Double Angle Formula for Sine

$\blacksquare$


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