# Intersection is Largest Subset/General Result

## Theorem

Let $T$ be a set.

Let $\mathcal P \left({T}\right)$ be the power set of $T$.

Let $\mathbb T$ be a subset of $\mathcal P \left({T}\right)$.

Then:

$\left({\forall X \in \mathbb T: S \subseteq X}\right) \iff S \subseteq \bigcap \mathbb T$

### Family of Sets

In the context of a family of sets, the result can be presented as follows:

Let $\family {S_i}_{i \mathop \in I}$ be a family of sets indexed by $I$.

Then for all sets $X$:

$\displaystyle \paren {\forall i \in I: X \subseteq S_i} \iff X \subseteq \bigcap_{i \mathop \in I} S_i$

where $\displaystyle \bigcap_{i \mathop \in I} S_i$ is the intersection of $\family {S_i}$.

## Proof

Let $\mathbb T \subseteq \mathcal P \left({T}\right)$.

Suppose that $\forall X \in \mathbb T: S \subseteq X$.

Consider any $x \in S$.

By definition of subset, it follows that:

$\forall X \in \mathbb T: x \in X$

Thus it follows from definition of set intersection that:

$x \in \bigcap \mathbb T$

Thus by definition of subset, it follows that:

$S \subseteq \bigcap \mathbb T$

So:

$\left({\forall X \in \mathbb T: S \subseteq X}\right) \implies S \subseteq \bigcap \mathbb T$

$\Box$

Now suppose that $S \subseteq \bigcap \mathbb T$.

From Intersection is Subset: General Result we have:

$\forall X \in \mathbb T: \bigcap \mathbb T \subseteq X$

So from Subset Relation is Transitive, it follows that:

$\forall X \in \mathbb T: S \subseteq \bigcap \mathbb T \subseteq X$

So it follows that $\forall X \in \mathbb T: S \subseteq X$.

So:

$S \subseteq \bigcap \mathbb T \implies \left({\forall X \in \mathbb T: S \subseteq X}\right)$

$\Box$

Hence:

$\left({\forall X \in \mathbb T: S \subseteq X}\right) \iff S \subseteq \bigcap \mathbb T$

$\blacksquare$

## Caution

Be careful of the way this result is stated:

$\left({\forall X \in \mathbb T: S \subseteq X}\right) \iff S \subseteq \bigcap \mathbb T$

Without the brackets, this would read:

$\forall X \in \mathbb T: S \subseteq X \iff S \subseteq \bigcap \mathbb T$

That is:

For all $X \in \mathbb T$, it is the case that $S \subseteq X$ if and only if $S \subseteq \bigcap \mathbb T$

This is not the same thing at all.

For example, if $\mathbb T = \mathcal P \left({T}\right)$ (as it well might), then $T \in \mathbb T$, and $\bigcap \mathbb T = \varnothing$.

This would imply that:

$T \subseteq \bigcap \mathbb T$

That is:

$T \subseteq \varnothing$

which is obviously rubbish.