Irreducible Polynomial/Examples/8 x^3 - 6 x - 1 in Rationals
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Examples of Irreducible Polynomials
Consider the polynomial:
- $\map P x = 8 x^3 - 6 x - 1$
over the ring of polynomials $\Q \sqbrk X$ over the rational numbers.
Then $\map P x$ is irreducible.
Proof
Aiming for a contradiction, suppose $\map P x$ has proper factors.
Then one of these has to be of degree $1$.
Thus from Factors of Polynomial with Integer Coefficients have Integer Coefficients we have:
- $8 x^3 - 6 x - 1 = \paren {a x + b} \paren {c^2 + d x + e}$
for some $a, b, c, d, e \in \Z$.
Hence:
\(\ds a c\) | \(=\) | \(\ds 8\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds a\) | \(\divides\) | \(\ds 8\) | |||||||||||
\(\ds b e\) | \(=\) | \(\ds -1\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds b\) | \(\divides\) | \(\ds 1\) |
The only possible degree $1$ factors with integer coefficients are:
- $x \pm 1, 2 x \pm 1, 4 x \pm 1, 8 x \pm 1$
By trying each of these possibilities, it is determined that no integer value of $d$ gives the correct values.
Hence the result.
$\blacksquare$
Sources
- 1969: C.R.J. Clapham: Introduction to Abstract Algebra ... (previous) ... (next): Chapter $6$: Polynomials and Euclidean Rings: $\S 31$. Polynomials with Integer Coefficients: Example $59$