Kuratowski's Theorem
Theorem
The following conditions on a graph $\Gamma$ are equivalent:
- $(1): \quad \Gamma$ is planar
- $(2): \quad \Gamma$ contains no subdivision of either the complete graph $K_5$ or the complete bipartite graph $K_{3, 3}$.
Proof
Let $\Gamma$ be a graph with $V$ vertices, $E$ edges and $F$ faces.
The proof proceeds in two parts: $(1) \implies (2)$ and $(2) \implies (1)$.
$(1)$ implies $(2)$
First we consider $K_5$.
$K_5$ has $5$ vertices and $10$ edges.
By the Euler Polyhedron Formula, a planar embedding would have $7$ faces.
But each face has at least $3$ edges, while each edge bounds at most two faces.
Suppose we count the incident edge-face pairs.
Then the number of faces is at most:
- $E \dfrac 2 3 = 6 \dfrac 2 3$
which contradicts the deduction that $K_5$, if planar, should have $7$ faces.
Hence $K_5$ is non-planar.
Now consider $K_{3, 3}$.
$K_{3, 3}$ has $6$ vertices and $9$ edges.
Hence $K_{3, 3}$ has $5$ faces if it is planar.
Since $K_{3, 3}$ is bipartite, from Graph is Bipartite iff No Odd Cycles, each cycle in $K_{3,3}$ has an even number of edges.
Hence any face must have at least $4$ edges.
So the number of faces is at most
- $E \dfrac 2 4 = 4 \dfrac 1 2$
which contradicts the deduction that $K_{3, 3}$, if planar, should have $5$ faces.
Hence $K_{3, 3}$ is non-planar.
Now consider a subdivision of either graph.
The arguments as above continue to work as before, since both $V$ and $E$ have increased by one in the Euler formula.
So the expected value of $F$ is unchanged.
Hence if a graph $\Gamma$ contains a subdivision of $K_5$ or $K_{3,3}$, then $\Gamma$ is not planar.
Taking the contrapositive:
- $\Gamma$ is a planar graph $\implies \Gamma$ does not contain a subdivision of either $K_5$ or $K_{3, 3}$.
$(2)$ implies $(1)$
![]() | This theorem requires a proof. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Source of Name
This entry was named for Kazimierz Kuratowski.
Sources
- 2014: Christopher Clapham and James Nicholson: The Concise Oxford Dictionary of Mathematics (5th ed.) ... (previous) ... (next): Kuratowski's Theorem
- 2021: Richard Earl and James Nicholson: The Concise Oxford Dictionary of Mathematics (6th ed.) ... (previous) ... (next): Kuratowski's Theorem