Number of Permutations with Repetition
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Theorem
Set $S$ be a set of $n$ elements.
Let $\sequence T_m$ be a sequence of $m$ terms of $S$.
Then there are $n^m$ different instances of $\sequence T_m$.
Proof
Let $N_m$ denote the set $\set {1, 2, \ldots, m}$.
Let $f: N_m \to S$ be the mapping defined as:
- $\forall k \in N_m: \map f t = t_m$
By definition, $f$ corresponds to one of the specific instances of $\sequence T_m$.
Hence the number of different instances of $\sequence T_m$ is found from Cardinality of Set of All Mappings:
- $\card S^{\card {N_m} }$
The result follows.
$\blacksquare$
Examples
$7$ Choices from $4$
Residents of a boarding house are offered a choice of $1$ of $4$ main foods for breakfast:
- fish or eggs or bacon or sausages.
Over the course of a week, a resident can then order:
- $1$ of $4$ dishes on Monday
- $1$ of $4$ dishes on Tuesday
- $\ldots$
- $1$ of $4$ dishes on Sunday
The number of different breakfast arrangements over a week of $7$ days is:
- $4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4 = 16 \, 384$
Sources
- 1932: Clement V. Durell: Advanced Algebra: Volume $\text { I }$ ... (previous) ... (next): Chapter $\text I$ Permutations and Combinations: The $r$, $s$ Principle: Example $3$.