Pandigital Product of Pandigital Pairs in 3 Ways

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Theorem

The pandigital integer $0 \, 429 \, 315 \, 678$ can be expressed as the product of a pandigital doubleton in $3$ different ways:


\(\ds 0 \, 429 \, 315 \, 678\) \(=\) \(\ds 04 \, 926 \times 87 \, 153\)
\(\ds \) \(=\) \(\ds 07 \, 923 \times 54 \, 186\)
\(\ds \) \(=\) \(\ds 15 \, 846 \times 27 \, 093\)


Proof

We have that:

$0 \, 429 \, 315 \, 678 = 2 \times 3^2 \times 11 \times 19 \times 139 \times 821$

Then:

\(\ds 04 \, 926 \times 87 \, 153\) \(=\) \(\ds \paren {2 \times 3 \times 821} \times \paren {3 \times 11 \times 19 \times 139}\)
\(\ds 07 \, 923 \times 54 \, 186\) \(=\) \(\ds \paren {3 \times 19 \times 139} \times \paren {2 \times 3 \times 11 \times 821}\)
\(\ds 15 \, 846 \times 27 \, 093\) \(=\) \(\ds \paren {2 \times 3 \times 19 \times 139} \times \paren {3 \times 11 \times 821}\)

$\blacksquare$


Sources