Primitive of x squared over x squared minus a squared/Logarithm Form
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Theorem
- $\ds \int \frac {x^2 \rd x} {x^2 - a^2} = x + \frac a 2 \map \ln {\frac {x - a} {x + a} } + C$
for $x^2 > a^2$.
Proof
Let:
\(\ds \int \frac {x^2 \rd x} {x^2 - a^2}\) | \(=\) | \(\ds \int \frac {x^2 - a^2 + a^2} {x^2 - a^2} \rd x\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \int \frac {x^2 - a^2} {x^2 - a^2} \rd x + \int \frac {a^2} {x^2 - a^2} \rd x\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \int \d x + a^2 \int \frac {\d x} {x^2 - a^2}\) | Primitive of Constant Multiple of Function | |||||||||||
\(\ds \) | \(=\) | \(\ds x + a^2 \int \frac {\d x} {x^2 - a^2} + C\) | Primitive of Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds x + a^2 \paren {\frac 1 {2 a} \map \ln {\frac {x - a} {x + a} } } + C\) | Primitive of $\dfrac 1 {x^2 - a^2}$: Logarithm Form | |||||||||||
\(\ds \) | \(=\) | \(\ds x + \frac a 2 \map \ln {\frac {x - a} {x + a} } + C\) | simplifying |
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 14$: Integrals involving $x^2 - a^2$, $x^2 > a^2$: $14.146$