# Pythagoras's Theorem/Proof 6

## Theorem

Let $\triangle ABC$ be a right triangle with $c$ as the hypotenuse.

Then:

$a^2 + b^2 = c^2$

## Proof

We have that $CH = BS = AB = AJ$.

Hence the result follows directly from Pythagoras's Theorem for Parallelograms.

$\blacksquare$

## Source of Name

This entry was named for Pythagoras of Samos.