Rational Number Space is Sigma-Compact
Jump to navigation
Jump to search
Theorem
Let $\struct {\Q, \tau_d}$ be the rational number space under the Euclidean topology $\tau_d$.
Then $\struct {\Q, \tau_d}$ is $\sigma$-compact.
Proof
From Rational Numbers are Countably Infinite, $\Q$ is countable.
Hence the result from definition of Countable Space is $\sigma$-Compact.
$\blacksquare$
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text {II}$: Counterexamples: $30$. The Rational Numbers: $8$