Segment of Auxiliary Relation is Subset of Lower Closure

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Theorem

Let $\left({S, \vee, \preceq}\right)$ be a bounded below join semilattice.

Let $R$ be auxiliary relation on $S$.

Let $x \in S$.


Then

$x^R \subseteq x^\preceq$

where

$x^R$ denotes the $R$-segment of $x$,
$x^\preceq$ denotes the lower closure of $x$.


Proof

Let $a \in x^R$.

By definition of $R$-segment of $x$:

$\left({a, x}\right) \in R$

By definition of auxiliary relation:

$a \preceq x$

Thus by definition of lower closure of element:

$a \in x^\preceq$

$\blacksquare$


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