Subset of Indiscrete Space is Sequentially Compact
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Theorem
Let $T = \struct {S, \set {\O, S} }$ be an indiscrete topological space.
Let $H \subseteq S$.
$H$ is sequentially compact in $T$.
Proof
From Sequence in Indiscrete Space converges to Every Point, every sequence in $T$ converges to every point of $S$.
So every infinite sequence has a subsequence which converges to every point in $S$.
Hence $H$ is (trivially) sequentially compact in $T$.
$\blacksquare$
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text {II}$: Counterexamples: $4$. Indiscrete Topology: $3$