Talk:Open Set Disjoint from Set is Disjoint from Closure
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To check - $A$ doesn't actually have to be open here right? The chain of reasoning only needs $S \setminus B$ to be closed. Caliburn (talk) 17:41, 14 March 2023 (UTC)
- I believe you are correct. This page was posted by someone who no longer contributes, so it is not possible to check with them where the result comes from.
- It is worth tracking back through to the pages which link to this, to see whether there is any dependency there to force $A$ to be open -- but even if there is, the result you suggest is stronger than this one. Hence I would have no immediate beef with the condition on $A$ being relaxed. Exactly how one would word the title is not a trivial problem, of course. --prime mover (talk) 18:25, 14 March 2023 (UTC)
- Would you amend the links while you're up here? If not I'll do it tomorrow. --prime mover (talk) 23:20, 14 March 2023 (UTC)