Talk:Resolvent Mapping is Analytic/Bounded Linear Operator

I am not sure why there is a rename request here. This is the natural title for this page. The notation $\map R {z; T}$ is perhaps a bit more common. Caliburn (talk) 09:46, 21 August 2023 (UTC)

My bad. When I posted this up it said: "Suppose $B$ is a Banach space, $\mathfrak{L}(B, B)$ is the set of bounded linear operators from $B$ to itself, and $T \in O$." WTF is $O$ we wonder? No worries, get rid. --prime mover (talk) 16:15, 21 August 2023 (UTC)